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x^2/x^2-6=3-2x/x^2-6
We move all terms to the left:
x^2/x^2-6-(3-2x/x^2-6)=0
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
Domain of the equation: x^2-6)!=0We get rid of parentheses
x∈R
x^2/x^2+2x/x^2-3+6-6=0
Fractions to decimals
2x/x^2-3+6-6+1=0
We multiply all the terms by the denominator
2x-3*x^2+6*x^2-6*x^2+1*x^2=0
We add all the numbers together, and all the variables
-2x^2+2x=0
a = -2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-2)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-2}=\frac{-4}{-4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-2}=\frac{0}{-4} =0 $
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